Solve each triangle. Give angle measures to the nearest degree
and side lengths to the nearest tenth.

please help :( I don't know how to show the work

1.

AB:

a² + b² = c²

'a' and 'b' are legs, while 'c' is the hypotenuse

3.6² + 5.2² = 12.96 + 27.04

c² = 40

c = √40

c ≈ 6.3

m∠A:

sine, cosine, tangent

soh -

cah -

toa -

∠a:

5.2 = opposite

6.3 = hypotenuse

= 0.825396...

x = sin^-1(0.825396)

x = 55.6 ≈ 56º

∠b:

90º + 56º = 146

180 - 146 = 34º

repeat for the rest of the problems

but which class are u may know that first

a

step-by-step explanation: