Hey can anyone pls pls pls help me out in dis math problem rq!!!

my mom deleted my padlet acc

Step-by-step explanation:

Step-by-step explanation:

eq. of line through (-3,-6) and (6,0) is

y+6=(0+6)/(6+3)(x+3)

y+6=6/9(x+3)

y+6=2/3(x+3)

3y+18=2x+6

3y=2x+6-18

3y=2x-12

put x=12,y=4

3×4=2×12-12

12=12

which shows (12,4) lies on above line.

∴inequality may be 3y≤2x-12

put x=0,y=0

0≤-12

which is not true .

Hence (0,0) does not lie in the inequality.

put x=8,y=-2

in the inequality.

3×-2≤2×8-12

-6≤16-12

or-6≤4

which is true.

Hence reqd. inequality is

3y≤2x-12

l.jnl.j/n.m,lm,

step-by-step explanation: