The mean weight of females in a class is 60kg and that of the males is 72kg. If the mean

weight of the class is 68kg, what is the ratio of females to males in the class?

1:2

Step-by-step explanation:

Let's say there are x males and y females in the class.

The sum of all male weights will be 72x, and the sum of all female weights will be 60y.

If we get a class mean weight, we have:

(72x + 60y) / (x+y) = 68

72x + 60y = 68x + 68y

4x = 8y

y / x = 4/8 = 1/2

So the ratio of females to males is the class is 1:2

answer: 1 + 1 = 11

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204