Find the volume of a pyramid with a square base, where the perimeter of the base is
10.1
ft
10.1 ft and the height of the pyramid is
13.4
ft
13.4 ft. Round your answer to the nearest tenth of a cubic foot.

9514 1404 393

  28.5 ft³

Step-by-step explanation:

The side length of the base is 1/4 of the perimeter, so is ...

  s = (10.1 ft)/4 = 2.525 ft

The area of the square base is the square of the side length, so is ...

  B = s² = (2.525 ft)² = 6.375625 ft²

The volume is given by ...

  V = 1/3Bh . . . . . where h is the height

  V = 1/3(6.375625 ft²)(13.4 ft) ≈ 28.4778 ft³

The volume of the pyramid is about 28.5 ft³.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2