One canned orange juice is 25% orange juice another is 5% orange juice. How many liters of each should be mixed together in order to get 20 L that is 8% orange juice

 (3)

Replcaing equation (3) into equation (2) we got:

And solving for Y we got:

And solving for X from equation (3) we got:

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration

Step-by-step explanation:

For this problem we can work with the concentration of water and orange juice.

Let X the amount for the orange juice with 25% content and Y the amount for the orange juice with 5% of content

Using the concentration of orange juice we have:

 (1)

And for the water we have:

 (2)

If we solve for X from equation (1) we got:

 (3)

Replcaing equation (3) into equation (2) we got:

And solving for Y we got:

And solving for X from equation (3) we got:

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°