A population of adult males had their heights measured. The heights were normally distributed. Approximately
what percentage of the heights, rounded to the nearest whole number, are within one standard deviation of the
mean?

The percentage of the heights that lie within one standard deviation of the mean height is 68%.

Step-by-step explanation:

Here it is given that the heights of adult males of a population are distributed normally.

The Empirical Rule states that in a normal distribution with mean µ and standard deviation σ, nearly all the data will fall within 3 standard deviations of the mean. The empirical rule can be divided into three parts:

        That is P (µ - σ ≤ X ≤ µ + σ) = 0.68.

        That is P (µ - 2σ ≤ X ≤ µ + 2σ) = 0.95.

        That is P (µ - 3σ ≤ X ≤ µ + 3σ) = 0.997.

So, the percentage of the heights that lie within one standard deviation of the mean height is 68%.

3/8

step-by-step explanation:

total income = price of one ticket   *   number of tickets sold

  y                 =     4                                   x

so the equation is y=4x     with x≥0   because number of tickets sold can not be negative

thus the equation is a semi -line with an end point at

(0,0)

passing through :

x=1     y=4(1) = 4   so through (1,4)