Si agrupo mis lápices de 2 en dos me sobra 1; si lo hago de 3 en 3, también me sobra 1 y si lo hago de 5 en 5 ocurre los mismo.¿Cuántos lápices tengo si son más de 30 y menos de 40?

31 pencils

Step-by-step explanation:

What we must do is reduce the range of responses, the first thing is to limit the numbers to the interval between 30 and 40.

If it is two by two and there is one left, it means that all the pairs are eliminated.

If it is five in five and there is one left over, the ones ending in 5 are also eliminated.

If it is three by three and there is one left over, the 33 and 39 are eliminated.

Taking this into account, the possibilities are reduced to two numbers only, 31 and 37.

37 is discarded because when it is grouped from five to five, there are 2 left over.

So the answer is 31, you have 31 pencils.

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.