(10 points) Consider the initial value problem y′+3y=9t, y(0)=7. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below). = help (formulas) Solve your equation for Y(s). Y(s)=L{y(t)}=

The solution

Step-by-step explanation:

Explanation:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

Step(i):-

Given differential problem

                           y′+3 y=9 t

Take the Laplace transform of both sides of the differential equation

                L( y′+3 y) = L(9 t)

 Using Formula Transform of derivatives

                L(y¹(t)) = s y⁻(s)-y(0)

   By using Laplace transform formula

Step(ii):-

Given

             L( y′(t)) + 3 L (y(t)) = 9 L( t)

Taking common y⁻(s) and simplification, we get

Step(iii):-

By using partial fractions , we get

 On simplification we get

  9 = A s(s+3) +B(s+3) +C(s²) ...(i)

 Put s =0 in equation(i)

   9 = B(0+3)

   B = 9/3 = 3

  Put s = -3 in equation(i)

  9 = C(-3)²

  C = 1

 Given Equation  9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

  9 = A s²+3 A s +B(s)+3 B +C(s²)

  0 = A + C

put C=1 , becomes A = -1

Step(iv):-

Applying inverse Laplace transform on both sides

By using inverse Laplace transform

Final answer:-

Now the solution , we get

d is correct

step-by-step explanation: