Robert is lying on the ground, looking at the top of a flagpole. The angle of elevation to the top of the flagpole is 25°. What is the height of the flagpole if the distance from his eyes at the ground to the base of the flagpole is 200 ft?

height of the flagpole = 93.26 ft

Step-by-step explanation:

The illustration  forms a right angle triangle. The angle of elevation from his eyes to the flag is 25° . The distance from his eyes at the ground to the base of the flagpole is 200 ft.

The adjacent side of the triangle formed is the distance of his eyes from the flagpole. The height of the flagpole is the opposite side of the right angle triangle formed.

using tangential ratio

tan 25° = opposite/adjacent

tan 25° = x/200

cross multiply

200 tan 25° = x

x = 200 × 0.46630765815

x = 93.261531631

x = 93.26 ft

height of the flagpole = 93.26 ft

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh

he has 140 chickens because he has 10 times more chickens than ducks and he has 14 ducks so 14*10=140