Write the first five terms of the sequence defined by the function below.

The first 5 terms are;

-2, 2, 13,38 and 91

Step-by-step explanation:

Here, we want to write the first 5 terms of the sequence.

We already have the first term as 1

Now, we need the 2nd term

Putting two in place of n, we have ;

2f(1) + 3n

= 2(-2) + 3(2) = -4 + 6 = 2

For the 3rd term, put 3 in place of n

2f(2) + 3(3)

sine f(2) = 2, we have

2(2) + 9 = 4+ 9 = 13

For the fourth term, put 4 in place of n, we have

2f(3) + 3(4)

since f(3) = 13

we have; 2(13) + 12 = 26 + 12 = 38

For the 5th term, put 5 in place of n, we have

2f(4) + 3(5)

since f(4) = 38, we have

2(38) + 15 = 76 + 15 = 91

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

( - 4 , -7 )

all the lines must parallel  

step-by-step explanation:

coordinates of c = ( - 1 , 2 )

3 units left = ( -4 , 2 )

9 units down = ( - 4 , 11 )