Fill in the blanks in the following proof.

Table :

     Statements                 Reasons

1)ΔEGC≅ΔEGB                 Given

2)EB = EC                          Corresponding Parts of Congruent

                                          Triangles are Congruent

3) BC = BE                         Given

4) By 2 and 3                      EB≅EC≅BC

5)∠BEC = 60°                     ΔBEC is an equilateral triangle

Step-by-step explanation:

We are given that BE = BC  ---1

We are also given that ΔEGC≅ΔEGB

So, BE = CE(Corresponding Parts of Congruent Triangles are Congruent) ---2

Now By 1 and 2

BE=BC=CE

In ΔBEC

BE=BC=CE

Since all sides are equal . So, it is an equilateral triangle

All angles of equilateral triangle are also equal i.e. 60°

So, ∠BEC = 60°

Hence proved

Table :

     Statements                 Reasons

1)ΔEGC≅ΔEGB                 Given

2)EB = EC                          Corresponding Parts of Congruent

                                          Triangles are Congruent

3) BC = BE                         Given

4) By 2 and 3                      EB≅EC≅BC

5)∠BEC = 60°                     ΔBEC is an equilateral triangle

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.