Circle P has a radius of 5 centimeters. Point Q lies on circle P, and the equation of is . Which equation could be the equation of a line tangent to circle P at point Q?

A. 2x + 5y = 1

B. 2x + y = 3

C. 5x + 2y = 7

D. 2x – 5y = 2

if y=4x then you will substitute 4x in for y in the second equation.

8x + 4x = 18 combine like terms

12x = 18 divide by 12 on both sides

x = 18/12 or 3/2

now replace x in the first equation with 3/2 to get

y = 4 3/2

y = 6

the answer is a

(3/2,6)

hope that .

brainliest is always apprectiated

mrbilldoesmath!

answer: a parabola

steps:

(x-1)(x+4)   = x(x+4) - 1(x+4) = (x^2 + 4x) - (x+4)

                = x^2 +4x -x -4   = x^2 +3x -4

which is a parabola

mrb