Gary needs to solve 120 problems by a certain day. He calculated, that to finish all the problems in time, he needs to solve 5 problems every day. But Gary's family is going on a trip, and for 4 days Gary will simply have no time to do math. How many problems will he need to be solving every day when he is not on a trip to still be done in time?

To be done in time, he would need to solve 6 questions per day on the days that he is not on trip

Step-by-step explanation:

If he solves the problems 5 per day, the total number of days that would be required to finish solving the problem would be 120/5 = 24 days

Now, he has 4 free days which would be for a family trip. The number of questions that he would miss during those trip days will be 4 * 5 = 20 questions

Now since he wants to still finish on time, what is needed to be done is to share the 20 left overs amongst the 20 days which he has to work

This makes a total of 1 question per day

Adding this to the 5 questions per day he has before will be = 6 questions per day

for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)

nada

step-by-step explanation: