Two gongs strike at intervals of 24 and 40minutes respectively. At twist time will they strike together again if they start simultaneously at 12 noon? Hint: 60 minutes = 1 hour

They will sound together at 2pm

Step-by-step explanation:

Now, the first thing we need to calculate is , in how many minutes will the two gongs strike together.

To be able to do this, we need to calculate the least common multiple of the two numbers 24 and 40

The lowest common multiple between both is 120

This means that the two gongs will sound together at exactly 120 minutes

Now since 1 hour is 60 minutes, this means that 120 minutes will be = 120/60 = 2 hours

Since they both sounded together at 12 noon and the next time they will be sounding is next two hours, their sounding time will thus be 12 noon + 2 hours = 2 pm

each side has a different length.  

step-by-step explanation:

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."