Mathematics, 30.05.2020 15:58 jaystarr9395
A cellular phone system services a population of n l "voice users" (those who occasionally need a voice connection) and n 2 "data users" (those who occasionally need a data connection). We estimate that at a given time, each user will need to be connected to the system with probability PI (for voice users) or P2 (for data users), independent of other users. The data rate for a voice user is rl bits/sec and for a data user is r 2 bits/sec. The cellular system has a total capacity of c bits/sec. What is the probability that more users want to use the system than the system can accommodate
Answers: 1
Mathematics, 21.06.2019 19:50, Roshaan8039
Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
Answers: 3
Mathematics, 21.06.2019 20:00, bermudezs732
Graph the linear function using the slooe and y intercept
Answers: 2
A cellular phone system services a population of n l "voice users" (those who occasionally need a vo...
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