What are the first three terms of a geometric sequence in which a5=25 and the common ratio is 5?

, , 1

Step-by-step explanation:

The n th term of a geometric sequence is

= a₁

where a₁ is the first term and r the common ratio

Given

a₅ = 25 and r = 5, then

a₁ = 25

625 a₁ = 25 ( divide both sides by 625 )

a₁ = =

a₂ = 5 × a₁ = 5 × =

a₃ = 5 × a₂ = 5 × = 1

*face palms*

step-by-step explanation:

no

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: