Connor and Angie helped take attendance during their school's practice fire drill. If the actual count was between 77 and 89, inclusive, what is the most the absolute error could be? What is the most the percent error could be? Round your answer to the nearest tenth of a percent

±12

15.8% or 13.5 %

Step-by-step explanation:

Most absolute error would be when actual count was 77 or 89 but number counted was 89 or 77 respectively.

absolute error= 89-77 or 77-89

Percent error= 12/77 × 100 or 12/89× 100

she will travel a distance in the range of 3 - 11 miles

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2