Create a circle with center A and a radius of your choice. Create a point B on the circle, and find the coordinates of B. Draw the radius . What is the slope-intercept form of the equation of ? Show your work.

Corrected Question

Create a circle with center A and a radius of your choice. Create a point B on the circle, and find the coordinates of B. Draw the radius AB. What is the slope-intercept form (y = mx + b) of the equation of AB? Show your work.

y=0.62x+2

Step-by-step explanation:

In the attached circle drawn using Geogebra

Gradient of AB, where

Line AB intercepts the y-axis at y=2, therefore: b=2

The slope-intercept form of the line AB (in this case) is therefore:

y=0.62x+2

For every circle center A of radius r and point B chosen on the circumference, the equation of the line AB will be different.

You can try one of your own!!

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°