Jason and Melinda are both driving from Fort Worth, Texas, to Van Horn, Texas. Jason leaves at 8:30 and averages 60 mph (miles per hour) on the way. Melinda leaves at 9:00 and averages 70 mph on the way. The situation is modeled by this system, where x is the number of hours after melinda leaves and y is the distance each will travel : y=60 x+30 y=70 How long after Melinda leaves will she pass Jason, and how far will they each have traveled?

Melinda will pass Jackson 3 hours after she leaves.

They will have traveled 210 miles.

Step-by-step explanation:

We need to build linear functions for their positions starting at 9 am.

We choose 9 am because it is the time of the last person leaving.

Melinda:

Leaves at 9 (from position 0).

Averages 70 mph.

So

Jason:

Leaves at 8:30, 60 mph.

At 9, when Melinda leaves, 30 minutes(half an hour will have passed). He will be at the position 0.5*60 = 30. So

How long after Melinda leaves will she pass Jason

This is t for which:

Melinda will pass Jackson 3 hours after she leaves.

How far will they each have traveled?

Either or . They are the same value.

They will have traveled 210 miles.

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation:

let's fu(!

step-by-step explanation: