If tan Theta = StartFraction 11 Over 60 EndFraction, what is the value of cot Theta? StartFraction 1 Over 60 EndFraction StartFraction 1 Over 11 EndFraction StartFraction 60 Over 11 EndFraction StartFraction 61 Over 11 EndFraction

Option C: StartFraction 60 Over 11 EndFraction

Step-by-step explanation:

if tan θ = 11/60, what is the value of cot θ?

cot θ is the reciprocal of tan θ

cot θ = 1/ tan θ

cot c = 1 ÷ (11/60)

cot θ = 1 x (60/11)

cot θ = 60/11.

the answer would be 150 books

step-by-step explanation:

if you divide 300 by 2 you will get 150

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)