Leon wants to estimate the proportion of the seniors at his high school who like to watch football. He interviews a simple random sample of 50 of the 200 seniors on campus. He finds that 32 like to watch football. Is the random condition for finding confidence intervals met? Explain.

Yes, the random conditions are met

Step-by-step explanation:

From the question, np^ = 32 and n(1 − p^) = 18.

Thus, we can say that:Yes, the random condition for finding confidence intervals is met because the values of np^ and n(1 − p^) are greater than 10.

Also, Yes, the random condition for finding confidence intervals is met because the sample size is greater than 30.

Confidence interval approach is valid if;

1) sample is a simple random sample

2) sample size is sufficiently large, which means that it includes at least 10 successes and 10 failures. In general a sample size of 30 is considered sufficient.

These two conditions are met by the sample described in the question.

So, Yes, the random conditions are met.

goog may have it for you

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!