The bag contains 100 candies: 23 candies on blue paper, 27 with green, 29 with red remaining with yellow

(a) which event is most likely to occur

1) taken candy with yellow or blue paper

2) Taken candy with green or red paper

2) is more likely.

Step-by-step explanation:

Number of yellow candies =  100 - 23 - 27 - 29 = 21,

Prob(Taking candy of yellow or blue) = (21 + 23) / 100 = 44/100.

Prob(Taking candy of green or red) = (27 + 29) / 100 = 56/100.

Therefore No 2) is more likely.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

80%

step-by-step explanation: