A company performs linear regressions to compare data sets for two similar
products. If the re...
Mathematics, 29.05.2020 08:58 maya8909
A company performs linear regressions to compare data sets for two similar
products. If the residuals for brand A are randomly scattered above and below the x-axis, and the residuals for brand B are also randomly scattered but clustered closer to the x-axis, what can be concluded?
A. A’s data are probably linear, while brand B’s data are probably not.
B. Brand B’s data are probably linear, while brand A’s data are probably not
C. Both data sets are probably linear.
D. Neither data set is likely to be linear.
Answers: 2
Mathematics, 21.06.2019 18:30, mikey8510
The median of a data set is the measure of center that is found by adding the data values and dividing the total by the number of data values that is the value that occurs with the greatest frequency that is the value midway between the maximum and minimum values in the original data set that is the middle value when the original data values are arranged in order of increasing (or decreasing) magnitude
Answers: 3
Mathematics, 21.06.2019 22:30, cbkhm
Tommy buys a sweater that is on sale for 40% off the original price. the expression p -0.4p can be used to find the sale price of the sweater, where p is the original price of the sweater. if the original price of the sweater is 50, what is the sale price?
Answers: 1
Mathematics, 22.06.2019 01:30, Falconpride4079
Drag the tiles to the correct boxes to complete the pairs. match the exponential functions with their horizontal asymptotes and y-intercepts. f(x) = 7x − 4 f(x) = 3x+2 + 4 f(x) = 9x+1 − 4 f(x) = 2x + 4 horizontal asymptote and y-intercept exponential function horizontal asymptote: y = 4 y-intercept: (0, 5) arrowboth horizontal asymptote: y = -4 y-intercept: (0, 5) arrowboth horizontal asymptote: y = -4 y-intercept: (0, -3) arrowboth horizontal asymptote: y = 4 y-intercept: (0, 13) arrowboth
Answers: 1
Mathematics, 17.09.2019 21:30
Mathematics, 17.09.2019 21:30
Mathematics, 17.09.2019 21:30