Mathematics, 28.05.2020 19:57 ashleyuchiha123

1. Suppose you have a dark closet containing seven blue shirts, five yellow shirts, and eight
white shirts. You pick two shirts at random from the closet. Find each probability.
a. P(blue then yellow) with replacing b. P(blue then yellow) without replacing
C. P(yellow then yellow) with replacing d. Plyellow then yellow) without replacing
e. P(yellow then white) with replacing f. P(yellow then white) without replacing
g. P(blue then blue) with replacing h. P(blue then blue) without replacing

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Answer from: bettycarter4573

A) P = 0.0875

B) P = 0.092

C) P = 0.0625

D) P = 0.053

E) P = 0.100

F) P = 0.105

G) P = 0.1225

H) P = 0.1105

Step-by-step explanation:

A) The probability of picking a blue shirt is $\frac{7}{20}$ . After replacing it, there are still 20 shirts, so the probability of picking a yellow shirt is $\frac{5}{20}$ . As the blue shirt AND the yellow shirt must be picked then you multiply the two probabilities together.

B) The probability of picking a blue shirt is $\frac{7}{20}$ . Without replacing it, there are 19 shirts, so the probability of picking a yellow shirt is $\frac{5}{19}$ . As the blue shirt AND the yellow shirt must be picked then you multiply the two probabilities together.

C) The probability of picking a yellow shirt is $\frac{5}{20}$ . After replacing it, there are still 20 shirts, so the probability of picking a yellow shirt is $\frac{5}{20}$ . As the yellow shirt AND the yellow shirt must be picked then you multiply the two probabilities together.

D) The probability of picking a yellow shirt is $\frac{5}{20}$ . Without replacing it, there are 19 shirts, so the probability of picking a yellow shirt is $\frac{4}{19}$ (as there is one less yellow shirt). As the yellow shirt AND the yellow shirt must be picked then you multiply the two probabilities together.

E) The probability of picking a yellow shirt is $\frac{5}{20}$ . After replacing it, there are still 20 shirts, so the probability of picking a white shirt is $\frac{8}{20}$ . As the yellow shirt AND the white shirt must be picked then you multiply the two probabilities together.

F) The probability of picking a yellow shirt is $\frac{5}{20}$ . Without replacing it, there are 19 shirts, so the probability of picking a white shirt is $\frac{8}{19}$ . As the yellow shirt AND the yellow shirt must be picked then you multiply the two probabilities together.

G) The probability of picking a blue shirt is $\frac{7}{20}$ . After replacing it, there are still 20 shirts, so the probability of picking a blue shirt is $\frac{7}{20}$ . As the blue shirt AND the yellow shirt must be picked then you multiply the two probabilities together.

H) The probability of picking a blue shirt is $\frac{7}{20}$ . Without replacing it, there are 19 shirts, so the probability of picking a blue shirt is $\frac{6}{19}$ (as there is one less blue shirt). As the blue shirt AND the blue shirt must be picked then you multiply the two probabilities together.

Answer from: Quest

Set square i think so

Answer from: Quest

i use my brain for prombles like this maybe you could try it

step-by-step explanation:

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1. Suppose you have a dark closet containing seven blue shirts, five yellow shirts, and eight
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