The endpoints of a diameter of a circle are located at(-3,6) and (7,-12). What is the equation of the circle? A. (×+2)2+(y+3)2=square 106 B. (X-4)2+(y+6)2

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Step-by-step explanation:

It is given that the endpoints of a diameter of a circle are located at(-3,6) and (7,-12). It means center of the circle is the midpoint of (-3,6) and (7,-12).

The center of the circle is (2,-3).

Radius is the distance between center and the endpoint of diameter. So, radius is equal to the distance between (2,-3) and (-3,6).

The standard form of the circle is

where, (h,k) is center and r is radius.

Substitute h=2, k=-3 and in the above equation.

Therefore, the required equation of circle is .

answer: 43/157

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