An expression is shown below.
f(x) = 2x2 - X - 10
Part B: Is the vertex of the graph of f(x) going to be a maximum or minimum? What are the coordinates of the vertex? Justify your answers and show your work. (3 points)
Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph. (5 points)

Step-by-step explanation:

f(x)=2x²-x-10

B.

it is upward parabola.

so vertex is minimum.

f(x)=2(x²-1/2x+(-1/4)²-(-1/4)²)-10

=2(x-1/4)²-2/16-10

=2(x-1/4)²-1/8-10

=2(x-1/4)²-81/8

vertex is (1/4,-81/8)

C.

when x=0,f(x)=-10

when f(x)=0,2x²-x-10=0

2x²-5x+4x-10=0

x(2x-5)+2(2x-5)=0

(2x-5)(x+2)=0

x=-2,5/2

it cuts x-axis at (-2,0) and (5/2,0)

and vertex is (1/4,-81/8)

1

step-by-step explanation:

it's the only multiple of both and the least

1. 34

2. 268

3. x=14.4

step-by-step explanation: