I ONLY HAVE THREE ATTEMPTS ON THIS ASSIGNMENT, AND I CANNOT FAIL.

A card is randomly drawn from a shuffled deck of cards and NOT REPLACED. A second card is drawn from the remaining shuffled cards. What is the approximate probability that both cards are RED?

THE ANSWER IS NOT 24.5 OR 25.

A. 24.5%

B. 25%

C. 49%

D. 50%

In a  deck of 52 cards, there are 26 red cards.

The probability that the first drawn card is red:

P(A) = 26/52

Without replacement, the probability that the second drawn card is red:

P(B) = 25/51

Then, this dependent probability is calculated by:

P = P(A) x P(B) = (26/52) x (25/51) = 25/102 = 0.245 = 24.5%

Hope this helps!

:)

yes

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2