If angle A is congruent to itself by the Reflexive Property, which transformation could be used to prove ΔABC ~ ΔADE by AA similarity postulate?

triangles ABC and ADE, in which point B is between points A and D and point C is between points A and E

Translate triangle ABC so that point C lies on point D to confirm ∠C ≅ ∠D.

Dilate ΔABC from point A by the ratio segment AD over segment AB to confirm segment AD ~ segment AB.

Translate triangle ABC so that point B lies on point D to confirm ∠B ≅ ∠D.

Dilate ΔABC from point A by the ratio segment AE over segment AC to confirm segment AE ~ segment AC.

D. Translate triangle ABC so that point B lies on point D to confirm ∠B ≅ ∠D.

Step-by-step explanation:

Translation describes a function that moves a given figure through a certain distance. In this case, the dimensions of the object are not affected.

Dilation involves resizing a given figure. It affects the dimensions of the figure but the angles.

Given that;

<BAC = <DAC (common angle to the triangles)

To determine the transformation to prove that ΔABC ~ ΔADE by angle-angle (AA) similarity postulate, translate triangle ABC so that point B lies on point D to confirm ∠B ≅ ∠D.

If ∠B ≅ ∠D (comparison of angles)

then;

   ΔABC ~ ΔADE (Angle-Angle property)

300pi

step-by-step explanation:

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!