The lifespans of lions in a particular zoo
are normally distributed. The average lion
lives 10 years, the standard deviation is
1.4 years
Use the empirical rule
(68 - 95 - 99.7%) to estimate the
probability of a lion living less than 7.2
years.

From the empirical rule we know that we have within one deviation from the mean 68% of the values, within two deviations 95% and within 3 deviations 99.7%. We want to find the following probability:

We can use the z score formula given by:

And replacing we got:

So we want to find the probability that the data lies below 2 deviations from the mean and using the empirical rule we got:

Step-by-step explanation:

For this problem we know that the average lion lives with a mean of and the deviation is

From the empirical rule we know that we have within one deviation from the mean 68% of the values, within two deviations 95% and within 3 deviations 99.7%. We want to find the following probability:

We can use the z score formula given by:

And replacing we got:

So we want to find the probability that the data lies below 2 deviations from the mean and using the empirical rule we got:

hi there! my name is zalgo and i am here to you out today. the answer is pretty simple (in a way). this equation equals to 25.2!

i hope this answer !

"stay and stay proud! " - zalgo