The equation for the motion of an object with constant acceleration is d=vt+1/2 at^2 where d is distance traveled in ft, v is starting velocity in ft/s, a is acceleration in ft/s^2 and t is time in seconds. A racecar begins with a velocity of 200 ft/s and accelerates at 100 ft/s^2. Write an expression for the distance the car travels after t seconds. What is the GCF of the expression?

Given: ad¯¯¯¯¯ is an altitude. prove: ab2+ac2=cb2 right triangle a b c with right angle a. point d lies on side b c and segment a d is drawn. angle a d c is a right angle. drag and drop a reason into each box to correctly complete the two-column proof. statement reason ad¯¯¯¯¯ is an altitude, and ∠bac is a right angle. given ∠adb and ∠adc are right angles. definition of altitude ∠bac≅∠bda ? ∠bac≅∠adc ? ∠b≅∠b ? ∠c≅∠c reflexive property of congruence △abc∼△dba ? △abc∼△dac aa similarity postulate abbd=cbab ? ab2=(cb)(bd) cross multiply and simplify. acdc=cbac polygon similarity postulate ac2=(cb)(dc) cross multiply and simplify. ab2+ac2=ab2+(cb)(dc) addition property of equality ab2+ac2=(cb)(bd)+(cb)(dc) substitution property of equality ab2+ac2=(cb)(bd+dc) ? bd+dc=cb segment addition postulate ab2+ac2=cb2 substitution property of equality

Rewrite the point-slope equation in slope-intercept form: y - 3 = 2(x + 4)

Multiply and subtract these polynomials and simplify. enter your response in standard form (2x3 - 3x + 11) – (3x2 + 1)(4 – 8x)