A collection of items are used for the wrap up party of Captain America.

* A spinner with eight equally divided spaces numbered from one to eight.

* Two fair six-sided dice.

* Two fair coins.

* A bag that contains four blue marbles, four red marbles, and eight yellow marbles.

* A standard deck of 52 cards.

Captain America decides to roll both fair sided dice. What is the probability he rolls an even number on one die and the number 1 on the second die? Write your answer as a fraction. Use the / (forward slash) ex. 3/5 **make sure your fraction is in simplified form

1/12

Step-by-step explanation:

Let the sample space be S.

Let the event of obtaining an even number on one dice and 1 on the other dice be E.

The sample space (S) of rolling a two fair six-sided dice is shown below:

1,1 1,2 1,3 1,4 1,5 1,6

2,1 2,2 2,3 2,4 2,5 2,6

3,1 3,2 3,3 3,4 3,5 3,6

4,1 4,2 4,3 4,4 4,5 4,6

5,1 5,2 5,3 5,4 5,5 5,6

6,1 6,1 6,3 6,4 6,5 6,6

n(S) = 36

The event (E) of obtaining an even number on one dice and 1 on the other dice is given below:

2,1 4,1 6,1

Therefore, n(E) = 3

The probability of obtaining an even number on one dice and 1 on the other dice is given below:

P(E) = n(E) / n(S)

P(E) = 3/36

P(E)= 1/12

Therefore, the probability of obtaining an even number on one dice and 1 on the other dice is 1/12

answer: she must produce at least 9,000 windows in order to make a profit of $48,000

explanation:

48,000 - 12,000 = 36,000

36,000/4 = 9,000

i have no clue at all sorry

step-by-step explanation: