Two functions are given below: f(x) and h(x). State the axis of symmetry for each function and explain how to find it.
f(x) = −2(x − 4)2 + 2
h(x)=

Axis of symmetry of f(x) is  at x=4

Axis of symmetry for h(x) is  at x=-2

Given :

The given f(x) is in the form of f(x)=a(x-h)^+k

The axis of symmetry lies at x=h

In the given f(x), the value of h is 4

From the given f(x), the axis of symmetry is  at x=4

Now we consider the graph of h(x)

The axis of symmetry lies at the x coordinate of vertex

In the graph , vertex is (-2,2)

x coordinate of vertex is -2

Axis of symmetry for h(x) is  at x=-2

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Answers are below

Step-by-step explanation:

The axis of symmetry for f(x) is at x = 4 because it splits the function in half. I found it by looking at the vertex of the parabola and using the x-value as the axis of symmetry.

The axis of symmetry for h(x) is at x = -2 because it splits the function in half. I found it by looking at the vertex of the parabola and using the x-value as the axis of symmetry.

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