A study of 4,430 U. S. adults found that 2,913 were obese or overweight. The 95% confidence interval for the proportion of adults in U. S. who are obese or overweight is .

(0.646, 0.669)

(0.644, 0.672)

(0.639, 0.676)

(0.650, 0.665)

We ar confident that the true proportion of people in US who are obes is between 0.644 and 0.672

And the best option is given by:

(0.644, 0.672)

Step-by-step explanation:

For this case we can begin calculating the proportion of people overweight with this formula:

The confidence level is 95% , and the significance level would be given by and . And the critical value would be given by:

The confidence interval for the mean is given by the following formula:  

Replacing the info given we got:

We ar confident that the true proportion of people in US who are obes is between 0.644 and 0.672

And the best option is given by:

(0.644, 0.672)

40% off the regular price is the correct answer.

step-by-step explanation:

step-by-step explanation:

divide, then simplify your answer.

1. make -15.66 ÷   5.8 a fraction. then divide.

2. simplify.  

3. final answer.