A deck of cards contains red cards number 23 blue cards numbered 1 2 3 4 and green cards numbered one to if a single card is picked at random what is the probability that the card is blue or has an odd number

Correct question:

A deck of cards contains RED cards numbered 1,2,3, BLUE cards numbered 1,2,3,4, and GREEN cards numbered 1,2. If a single card is picked at random, what is the probability that the card is BLUE OR has an ODD number?

2/13

Step-by-step explanation:

Number of red cards = 3 (1,2,3)

Number of blue cards = 4 (1, 2, 3, 4)

Number of green cards = 2 (1,2)

Total number of cards in a deck = 52

Probability of picking a blue card OR has an odd number

P(picking a blue card ) = required outcome / possible outcome

P( picking a blue card ) = 4/52 = 1/13

P( odd number card ) = 6/52 = 3/26

P(blue and odd) = 2/52 = 1/26

P(picking a blue card or an odd number )

P(picking a blue ) U P(picking an odd number)

P(picking a blue) + (P(picking an odd) - P(picking a blue odd)

1/13 + 3/26 - 1/26= (2 + 3 - 1)/26 = 4/26 = 2/13

4444444444444 i think

what is the rest of the question? ?