If a couple were planning to have three children, the sample space summarizing the gender outcomes would be: bbb, bbg, bgb, bgg, gbb, gbg, ggb, ggg. a. Construct a similar sample space for the possible eye color outcomes (using b for blue dash eyed and g for green dash eyed) of two children. b. Assuming that the outcomes listed in part (a) were equally likely, find the probability of getting two green dash eyed children. c. Find the probability of getting exactly one blue dash eyed child and one green dash eyed child.

a) bb, bg, gb, gg

b) 25% probability of getting two green dash eyed children.

c) 50% probability of getting exactly one blue dash eyed child and one green dash eyed child.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

Total of eight outcomes.

a. Construct a similar sample space for the possible eye color outcomes (using b for blue dash eyed and g for green dash eyed) of two children.

bb, bg, gb, gg

b. Assuming that the outcomes listed in part (a) were equally likely, find the probability of getting two green dash eyed children.

Four outcomes.

Of those, in one(gg), you get two green dash eyed children.

1/4 = 0.25

25% probability of getting two green dash eyed children.

c. Find the probability of getting exactly one blue dash eyed child and one green dash eyed child.

In two of those(bg and gb) you get one blue dash eyed child and one green dash eyed child.

2/4 = 0.5

50% probability of getting exactly one blue dash eyed child and one green dash eyed child.

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

$25

step-by-step explanation:

25 - 4.50 = 20.5

20.5 / 2 = 10.25

10.25 + 10 = 20.25

20.25 - 12.50 = 7.75

therefore the answer is $25 as shown as the first number.