Referring to the table below, what's the probability of someone in the survey being either older than 30 or not owning a car?

Denote:

Probability of not owning a car: P(A) = 0.35

Probability of being older than 30: P(B) = 0.6

Probability of not owning a car and being older than 30: P(A⋂B) = 0.21

=> Probability of either not owning a car or being older than 30:

P(A⋃B) = P(A) + P(B) - P(A⋂B) = 0.35 + 0.6 - 0.21 = 0.74

=> Option D is correct

Hope this helps!

:)

d. 74%

Step-by-step explanation:

P(>30) + P(no car) - P(both)

0.60 + 0.35 - 0.21

0.74 × 100

74%

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5