The range R and the maximum height H of a projectile fired at an inclination to the horizontal with initial speed vo are
given by the formulas below, where g 322 feet per second per second is the acceleration due to gravity
A. Find the range R if the projectile is fired at an angle of 45° to the horizontal with an initial speed of 140 feet per second.
R= ? feet (Round to two decimal places as needed.)

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

y=35

x=5

step-by-step explanation: