1. A researcher would like to learn about the difference in proportions of students and faculty who support textbook price caps. The researcher gathers a random sample of 500 students and 500 faculty members and asks whether or not they support textbook price caps. 378 students and 256 faculty members say they support capping prices. Construct a 95% confidence interval for the difference of the population proportions. Round the confidence interval limits to three decimal places.

(0.186, 0.298)

Step-by-step explanation:

The formula to find the confidence interval for the difference of the population proportion is given by :-

  ... (i)

, where Sample size of population 1.

 Sample size of population 2.

Sample proportion of population 1.

= Sample proportion of population 2.

z* = Critical z-value corresponding to confidence interval

As per given , we have

Critical value corresponds to 95% confidence interval = 1.96

Put all these values , in (i) , we get

Hence, the 95% confidence interval for the difference of the population proportions= (0.186, 0.298)

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m