10x2-6=9x
Two solutions were found :
x =(9-√321)/20=-0.446
x =(9+√321)/20= 1.346
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
10*x^2-6-(9*x)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((2•5x2) - 6) - 9x = 0
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 10x2-9x-6
The first term is, 10x2 its coefficient is 10 .
The middle term is, -9x its coefficient is -9 .
The last term, "the constant", is -6
Step-1 : Multiply the coefficient of the first term by the constant 10 • -6 = -60
Step-2 : Find two factors of -60 whose sum equals the coefficient of the middle term, which is -9 .
-60 + 1 = -59
-30 + 2 = -28
-20 + 3 = -17
-15 + 4 = -11
-12 + 5 = -7
-10 + 6 = -4
-6 + 10 = 4
-5 + 12 = 7
-4 + 15 = 11
-3 + 20 = 17
-2 + 30 = 28
-1 + 60 = 59
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 2 :
10x2 - 9x - 6 = 0
Step 3 :
Parabola, Finding the Vertex :
3.1 Find the Vertex of y = 10x2-9x-6
Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 10 , is positive (greater than zero).
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.
For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is 0.4500
Plugging into the parabola formula 0.4500 for x we can calculate the y -coordinate :
y = 10.0 * 0.45 * 0.45 - 9.0 * 0.45 - 6.0
or y = -8.025
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = 10x2-9x-6
Axis of Symmetry (dashed) {x}={ 0.45}
Vertex at {x,y} = { 0.45,-8.03}
x -Intercepts (Roots) :
Root 1 at {x,y} = {-0.45, 0.00}
Root 2 at {x,y} = { 1.35, 0.00}
Solve Quadratic Equation by Completing The Square
3.2 Solving 10x2-9x-6 = 0 by Completing The Square .
Divide both sides of the equation by 10 to have 1 as the coefficient of the first term :
x2-(9/10)x-(3/5) = 0
Add 3/5 to both side of the equation :
x2-(9/10)x = 3/5
Now the clever bit: Take the coefficient of x , which is 9/10 , divide by two, giving 9/20 , and finally square it giving 81/400
Add 81/400 to both sides of the equation :
On the right hand side we have :
3/5 + 81/400 The common denominator of the two fractions is 400 Adding (240/400)+(81/400) gives 321/400
So adding to both sides we finally get :
x2-(9/10)x+(81/400) = 321/400
Adding 81/400 has completed the left hand side into a perfect square :
x2-(9/10)x+(81/400) =
(x-(9/20)) • (x-(9/20)) =
(x-(9/20))2
Things which are equal to the same thing are also equal to one another. Since
x2-(9/10)x+(81/400) = 321/400 and
x2-(9/10)x+(81/400) = (x-(9/20))2
then, according to the law of transitivity,
(x-(9/20))2 = 321/400
We'll refer to this Equation as Eq. #3.2.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(x-(9/20))2 is
(x-(9/20))2/2 =
(x-(9/20))1 =
x-(9/20)
Now, applying the Square Root Principle to Eq. #3.2.1 we get:
x-(9/20) = √ 321/400
Add 9/20 to both sides to obtain:
x = 9/20 + √ 321/400
Since a square root has two values, one positive and the other negative
x2 - (9/10)x - (3/5) = 0
has two solutions:
x = 9/20 + √ 321/400
or
x = 9/20 - √ 321/400
Note that √ 321/400 can be written as
√ 321 / √ 400 which is √ 321 / 20
Solve Quadratic Equation using the Quadratic Formula
3.3 Solving 10x2-9x-6 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 10
B = -9
C = -6
Accordingly, B2 - 4AC =
81 - (-240) =
321
Applying the quadratic formula :
9 ± √ 321
x = —————
20
√ 321 , rounded to 4 decimal digits, is 17.9165
So now we are looking at:
x = ( 9 ± 17.916 ) / 20
Two real solutions:
x =(9+√321)/20= 1.346
or:
x =(9-√321)/20=-0.446
Two solutions were found :
x =(9-√321)/20=-0.446
x =(9+√321)/20= 1.346
Step-by-step explanation:
