Jolon used the slope-intercept form to write the equation of a line with slope 3 that passes through the point (5, –2). His work is shown below.

Step 1: Negative 2 = 3 (5) + b
Step 2: negative 2 = 15 + b
Step 3: Negative 2 + 15 = 15 + 15 + b
Step 4: Negative 13 = b
Step 5: y = 3x – 13