In the cube shown below, the distance between vertices 2 and 6 is 8 cm.

If the cube is divided into two equal parts by a plane parallel to the face defined by vertices 1, 2, 3, and 4, what will be the perimeter of the cross-section?

256 sq cm

Step-by-step explanation:

cube is a three-dimensional figure with six congruent square faces. Since each face is congruent, each of the edges have the same length.

The cross-section described is shown below.

The cross-section is also a square which is congruent to the other faces of the cubes. Therefore, the edges of the cross-section will each measure 16 cm. Find the area by using the formula for the area.

          A=lw

              =(16cm) (16cm)

                 =256 sq cm  

So, the area of the cross-section is 256 sq cm.

hope this helps some way

44

Step-by-step explanation:

If you are doing study island just trust me this is the answer.

If the height is 11 then you multiply that by 4 for the four sides you get 44.

I know I didn't explain that right but that's how I figured it out.

i think the answer is b)

step-by-step explanation:

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3