The model of a mini-submarine has the dimensions shown. What is the volume of the mini-submarine?_pi units^3

138pi units^3

Step-by-step explanation:

To find the volume of the mini-submarine, we need to find the volume of its three parts: half sphere, cylinder and cone. Then, we sum the volumes of the three parts.

Volume of the half sphere with radius = 3:

V1 = (1/2) * (4/3) * pi * r^3

V1 = (1/2) * (4/3) * pi * 3^3 = 18pi units^3

Volume of the cylinder with radius = 3 and height = 12:

V2 = pi * r^2 * h

V2 = pi * 3^2 * 12 = 108pi units^3

To find the volume of the cone, we need to first find its height:

h^2 + r^2 = s^2

h^2 + 3^2 = 5^2

h = 4

Volume of the cone with radius = 3 and height = 4:

V3 = (1/3) * pi * r^2 * h

V3 = (1/3) * pi * 3^2 * 4 = 12pi units^3

The total volume will be:

V = V1 + V2 + V3 = 138pi units^3

no because mercury has a density of 13.6 grams per centimeter squared while gold has 19.32 grams centimeter squared

step-by-step explanation:

the correct answer is c

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