What is the slope of a line perpendicular to the line whose equation is

10x−8y=−8010x-8y=-80

10x−8y=−80. Fully reduce your answer.

The slope of the other line is -4/5

Step-by-step explanation:

In this question, we are asked to calculate the slope of a line which is perpendicular to the line ;

10x - 8y = -80

The first thing to do here is to write the equation in the standard form for a linear equation.

The standard form is y = mx + c where m refers to the slope and c refers to the y-intercept

Rewriting the equation we have;

8y-80 = 10x

8y = 10x + 80

Now divide the through by 8

We have;

y = 10x/8 + 10

Thus, comparing with y = mx + c , our m here is 10/8

Now for the two lines to be perpendicular, the product of their slope would be equals to -1

Let’s say the slopes are m1 and m2

mathematically m1m2 = -1

since m1 = 10/8

10m2/8 = -1

m2 = -8/10

m2 = -4/5

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