What is the surface area of the triangular prism represented by the net below?
640 cm2
10 cm
608 cm2
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16 cm
704 cm
Foam-12 cm
448 cm
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10 cm

608cm^2 (B)

Step-by-step explanation:

The question is incomplete without the diagram as this will ensure an accurate answer is given to the question.

Find attached the diagram used in solving the question.

Using the labelled diagram, we would find the surface area of the triangular prism.

Area of triangular prism = area of A + area of B + area of C + area of D + area of E

Shape of A and B are a triangles

Area of A = 1/2 × base × height

= 1/2 × 12 × 8 = 48cm^2

Area of B = Area of A = 48cm^2

Shape of C , D and E are rectangles

Area of C = Area of E (they have same width)

The width is the slant length = hypotenuse (hyp) of the triangle

To get the hypotenuse, we would apply Pythagoras theorem as can see from the diagram it is a right-angled triangle.

Opposite (opp) = 8cm

Adjacent (adj) = 12/2 = 6cm

Hyp^2 = opp^2 + adj^2

Hyp = √(8^2 +6^2) = √(64+36) = √100

Hyp = 10cm

Hypotenuse = width = 10cm

Area = length × width

Area = 16×10 = 160cm^2

Area of C = 160cm^2

Area of E = 160cm^2

Area of D = length × width

= 16×12 = 192cm^2

surface area of the triangular prism = 48+48+160+160+192

surface area of the triangular prism =608cm^2

42.4

step-by-step explanation:

convert to decimal

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

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