A researcher works on a study that has a population standard deviation of .73, a sample mean of 84.5, and a sample size of 60. a) What is the margin of error with a. confidence level of 95%? (0.109)(0.094)(0.188)(0.070)

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

is should be y = 5x

step-by-step explanation:

correct me if im wrong

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5