Watch help video
Jocelyn has x dimes and y quarters. She has a minimum of 16 coins worth no more
than $3 combined. Solve this system of inequalities graphically and determine one
possible solution.

20 dimes and 2  quarters

Step-by-step explanation:

x = number of dimes

y  = number of quarters

minimum is greater than or equal to ≥

x+y ≥16

no more than is less than or equal to ≤ ,

value of dime is $ 0.10

value of quarter is $0.25 so

0.10x + 0.25y ≤ 3.00

Rewrite inequalities in terms of y:

y ≥16 - x

(0.25/0.25)y ≤ (3.00/0.25)-(0.10/0.25)x→

y≤12 - 0.4x

Graph system: see file

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

attachment?

step-by-step explanation: