Which value of xis a solution to this equation?
16 + 2x = 36

Start by isolating the term containing x which is 2x.

To do this, subtract 16 from both sides.

On the left, the 16's cancel and we're left

with 2x andon the right, 36 - 16 is 20.

So we have 2x = 20.

Now since 2 is multiplied by x, divide both

sides of the equation by 2 to get x by itself.

On the left, the 2's cancel and we're left

with x and on the right, 20 divided by 2 is 10.

So we have x = 10 which is the solution to this equation.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )