Tickets numbered 1 to 20 are placed in a hat. Two tickets are drawn out at random, without
replacement. Find the probability that:
a: the first number drawn is even and the second number is odd
b: both of the numbers are prime.
-please help include explanation too, it would be really helpful if u can!-

a. 5/19, b. 14/95

Step-by-step explanation:

a. since the first number drawn has 10/20 chance of being even and it's not put back (you assume that you pull an even #), so the second number pulled has a 10/19 chance of being odd.

10/20*10/19 = 5/19

b. 2, 3, 5, 7, 11, 13, 17, 19 are the prime numbers, so 8/20 for the first pull and then 7/19 for the second pull

8/20*7/19 = 14/95

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

the solution is h=10 because you add 9 to each side of the equation.