Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 564 randomly selected adults showed that 56% of them would erase all of their personal information online if they could. Find the value of the test statistic.

The value of z test statistic is 2.871.

Step-by-step explanation:

We are given that a software firm survey of 564 randomly selected adults showed that 56% of them would erase all of their personal information online if they could. Find the value of the test statistic.

Let p = population proportion of adults who would erase all of their personal information online if they could.

So, Null Hypothesis, : p 50%      {means that adults who would erase all of their personal information online if they could is less than or equal to 50%}

Alternate Hypothesis, : p > 50%     {means that majority of adults would erase all of their personal information online if they could}

The test statistics that would be used here One-sample z test for proportions;

                            T.S. =    ~ N(0,1)

where, = sample proportion of adults who would erase all of their personal information online if they could = 56%

           n = sample of adults taken = 564

So, the test statistics  =  

                                       =  2.871

The value of z test statistic is 2.871.

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

.19875994384

step-by-step explanation:

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