The equation of a circle is given by (x + 3.5) ^ 2 + (y - 2.82) ^ 2 = 25 What is the area of a 52 degrees sector of this circle? Round to the nearest hundredth of a square unit.

≈ 11.34 units²

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 3.5)² + (y - 2.82)² = 25 ← is in standard form

with r² = 25 ⇒ r = = 5

The area (A) of the sector is calculated as

A = area of circle × fraction of circle

   = πr² ×

   = π × 5² ×

   = π × 25 ×

   =

   ≈ 11.34 units² ( to the nearest hundredth )

understand that i don't know the answers

will someone answer his question

according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

step-by-step explanation: